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JEE Mains · Maths · STD 12 - 11. three dimension geometry

જો રેખા \(\frac{x-1}{3}=\frac{2-y}{m}=\frac{z+3}{1}\) થી સમાંતર માપતા બિંદુ \((1,-2,3)\) નું સમતલ \(x+2 y-3 z+10=0\) થી અંતર \(\sqrt{\frac{7}{2}}\) હોય, તો \(\mid m \mid =..... .\)  

  1. A \(1\)
  2. B \(4\)
  3. C \(3\)
  4. D \(2\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2\)

Step-by-step Solution

Detailed explanation

\(DC\) of line \(\equiv\left(\frac{3}{\sqrt{ m ^{2}+10}}, \frac{- m }{\sqrt{ m ^{2}+10}}, \frac{1}{\sqrt{ m ^{2}+10}}\right)\) \(Q \equiv\left(1+\frac{3 r }{\sqrt{ m ^{2}+10}},-2+\frac{- mr }{\sqrt{ m ^{2}+10}}, 3+\frac{ r }{\sqrt{ m ^{2}+10}}\right)\) \(Q\) lies on…
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