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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

જો  \(\mathrm{e}_{1}\) અને  \(\mathrm{e}_{2}\) એ અનુક્રમે ઉપવલય \(\frac{\mathrm{x}^{2}}{18}+\frac{\mathrm{y}^{2}}{4}=1\) અને અતિવલય \(\frac{\mathrm{x}^{2}}{9}-\frac{\mathrm{y}^{2}}{4}=1\) ની  ઉકેન્દ્રીતા હોય  અને બિંદુ \(\left(\mathrm{e}_{1}, \mathrm{e}_{2}\right)\) એ ઉપવલય \(15 \mathrm{x}^{2}+3 \mathrm{y}^{2}=\mathrm{k},\) પર હોય તો  \(\mathrm{k}\) મેળવો.

  1. A \(15\)
  2. B \(14\)
  3. C \(17\)
  4. D \(16\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(16\)

Step-by-step Solution

Detailed explanation

\(e_{1}=\sqrt{1-\frac{4}{18}}=\frac{\sqrt{7}}{3}\) \(\mathrm{e}_{2}=\sqrt{1+\frac{4}{9}}=\frac{\sqrt{13}}{3}\) \(\because \quad\left(\mathrm{e}_{1}, \mathrm{e}_{2}\right)\) lies on \(15 \mathrm{x}^{2}+3 \mathrm{y}^{2}=\mathrm{k}\)…
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