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JEE Mains · Maths · STD 12 - 7.2 definite integral

જો \(f : (-1, 1) \to R\) એ સતત વિધેય છે  અને  \(\int\limits_0^{\sin \,x} {f\left( t \right)dt}  = \frac{{\sqrt 3 }}{2}x\) , તો  \(f\left( {\frac{{\sqrt 3 }}{2}} \right)\) ની કિમંત મેળવો.

  1. A \(\frac{1}{2}\)
  2. B \(\frac{{\sqrt 3 }}{2}\)
  3. C \(\sqrt {\frac{3}{2}} \)
  4. D \(\sqrt 3 \)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\sqrt 3 \)

Step-by-step Solution

Detailed explanation

Let \(f:\left( { - 1,1} \right) \to R\) be a continuous function Let \(\int\limits_0^{\sin x} {f\left( t \right)dt} = \frac{{\sqrt 3 }}{2}x\) \(f\left( {\sin x} \right).\frac{d}{{dx}}\left( {\sin x} \right) = \frac{{\sqrt 3 }}{2}\)…
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