ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 11. three dimension geometry

ધારોકે બિંદુ \((3,-2,5)\) માંથી પસાર થતા અને બિંદુુ \((1,2,3)\) તથા \((-2,3,5)\) ને જોડતી રેખા ને લંબ હોય તેવા સમતલનું સમીકરણ \(\alpha x+\beta y+\gamma z=1\) છે. તો \(\alpha \beta \gamma\) ની કીંમત \(...........\) છે.

  1. A \(5\)
  2. B \(6\)
  3. C \(4\)
  4. D \(9\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(6\)

Step-by-step Solution

Detailed explanation

Given Equation is not equation of plane as \(yz\) is present. If we consider \(y\) is \(\gamma\) then answer would be 6. Normal vector of plane \(=3 \hat{i}-\hat{j}-2 \hat{k}\) Plane : \(3 x-y-2 z+\lambda=0\) Point \((3,-2,5)\) satisfies the plane \(\lambda=-1\) \(3 x-y-2 z=1\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app