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JEE Mains · Maths · STD 11 - 4.1 complex nubers

જો \(\alpha ,\beta \in C\) એ સમીકરણ \({x^2} - x + 1 = 0\) ના ભિન્ન બીજ હોય તો \({\alpha ^{101}} + {\beta ^{107}}\) મેળવો.

  1. A \(0\)
  2. B \(1\)
  3. C \(2\)
  4. D \(-1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1\)

Step-by-step Solution

Detailed explanation

\(\alpha, \beta\) are roots of \(x^{2}-x+1=0\) \(\therefore \quad \alpha=-\omega\) and \(\beta=-\omega^{2}\) where \(\omega\) is cube root of unity \(\therefore \quad \alpha^{101}+\beta^{107}\) \(=(-\omega)^{101}+(-\omega)^{107}\) \(=-\left[\omega^{2}+\omega\right]=-[-1]=1\)
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