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JEE Mains · Maths · STD 11 - 13. statistics

જો આપેલ આવૃતિ વિતરણનો મધ્યક અને વિચરણ અનુક્રમે \(9\) અને\(15.08\) છે તો \(\alpha^2+\beta^2-\alpha \beta\) ની કિમંત મેળવો.
\(x_i\) \(2\) \(4\) \(6\) \(8\) \(10\) \(12\) \(14\) \(16\)
\(f_i\) \(4\) \(4\) \(\alpha\) \(15\) \(8\) \(\beta\) \(4\) \(5\)

  1. A \(24\)
  2. B \(23\)
  3. C \(25\)
  4. D \(22\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(25\)

Step-by-step Solution

Detailed explanation

\(N=\sum f_i=40+\alpha+\beta\) \(\sum f_i x_i=360+6 \alpha+12 \beta\) \(\sum f _{ i } x _{ i }^2=3904+36 \alpha+144 \beta\) \(\operatorname{Mean}(\overline{ x })=\frac{\sum f _{ i } x _{ i }}{\sum f _{ i }}=9\) \(\Rightarrow 360+6 \alpha+12 \beta=9(40+\alpha+\beta)\)…
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