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JEE Mains · Maths · STD 11 - 12. limits

ધારોકે \(a_1, a_2, a_3, \ldots, a_{ n }\) એ સમાંતર શ્રેણીના \(n\) ક્રમિક પદો છે. જો \(d > 0\) સામાન્ય તફાવત હોય, તો \(\lim _{n \rightarrow \infty} \sqrt{\frac{d}{n}}\left(\frac{1}{\sqrt{a_1}+\sqrt{a_2}}+\frac{1}{\sqrt{a_2}+\sqrt{a_3}}+\ldots \ldots \ldots+\frac{1}{\sqrt{a_{n-1}}+\sqrt{a_n}}\right)=........\)

  1. A \(1\)
  2. B \(\sqrt{ d }\)
  3. C \(\frac{1}{\sqrt{ d }}\)
  4. D \(0\)
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(A) \(1\)

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\(\lim _{n \rightarrow \infty} \sqrt{\frac{ d }{ n }}\left(\frac{1}{\sqrt{a_1}+\sqrt{a_2}}+\frac{1}{\sqrt{a_2}+\sqrt{a_3}}+\ldots \ldots \ldots+\frac{1}{\sqrt{a_{n-1}}+\sqrt{a_n}}\right)\) On rationalising each term…
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