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JEE Mains · Maths · STD 12 - 11. three dimension geometry

જો બિંદુ \((4,3,8)\) થી રેખા \(L _{1}: \frac{ x - a }{l}=\frac{ y -2}{3}=\frac{ z - b }{4},\) \(l \neq 0\) પરનો લંબપદ \((3,5,7)\) હોય, તો રેખા \(L _{1}\) અને રેખા \(L _{2}: \frac{ x -2}{3}=\frac{ y -4}{4}=\frac{ z -5}{5}\) વચ્ચેનું લઘૂતમ અંતર ..... થાય.

  1. A \(\frac{1}{2}\)
  2. B \(\frac{1}{\sqrt{6}}\)
  3. C \(\sqrt{\frac{2}{3}}\)
  4. D \(\frac{1}{\sqrt{3}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{\sqrt{6}}\)

Step-by-step Solution

Detailed explanation

\((3,5,7)\) satisfy the line \(L_{1}\) \(\frac{3-a}{\ell}=\frac{5-2}{3}=\frac{7-b}{4}\) \(\frac{3- a }{\ell}=1\) And \(\frac{7-b}{4}=1\) \(a+\ell=3 \quad \ldots(1)\) And \(b=3\) \(\overrightarrow{ v }_{1}=<4,3,8>-<3,5,7>\) \(\overrightarrow{ v }_{1}=<1,-2,1>\)…
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