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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

ધારો કે સમીકરણ સંહતિ \(x+2 y+3 z=5,2 x+3 y+z=9,4 x+3 y+\lambda z=\mu\) ને અસંખ્ય ઉકેલો છે. તો \(\lambda+2 \mu\) = ...........

  1. A \(28\)
  2. B \(17\)
  3. C \(22\)
  4. D \(15\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(17\)

Step-by-step Solution

Detailed explanation

\( x+2 y+3 z=5 \) \(2 x+3 y+z=9 \) \( 4 x+3 y+\lambda z=\mu\) for infinite following \(\Delta=\Delta_1=\Delta_2=\Delta_3=0\) \(\Delta=\left|\begin{array}{lll}1 & 2 & 3 \\ 2 & 3 & 1 \\ 4 & 3 & \lambda\end{array}\right|=0 \Rightarrow \lambda=-13\)…
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