ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 7.2 definite integral

\(\int \limits_{-1}^{1} \log _{ e }(\sqrt{1- x }+\sqrt{1+ x }) dx\) ની કિમંત મેળવો.

  1. A \(2 \log _{e} 2+\frac{\pi}{4}-1\)
  2. B \(\frac{1}{2} \log _{e} 2+\frac{\pi}{4}-\frac{3}{2}\)
  3. C \(2 \log _{\mathrm{e}} 2+\frac{\pi}{2}-\frac{1}{2}\)
  4. D \(\log _{e} 2+\frac{\pi}{2}-1\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\log _{e} 2+\frac{\pi}{2}-1\)

Step-by-step Solution

Detailed explanation

\(\text { Let } I=2 \int_{0}^{1} \underbrace{\operatorname{In}(\sqrt{1-x}+\sqrt{1+x})}_{(I)} \underbrace{1}_{(II)} d x\) \(\quad\quad\quad\quad\quad\quad\quad\quad(I.B.P.)\) \(\therefore I=\mid x \cdot I n(\sqrt{1-x}+\sqrt{1-x})_{0}^{1}\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app