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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

ધારો કે \(f\) અને \(g\) એ \((-2,2)\) પરનાં એવા દ્વિ વિકલનીય ચુગ્મ વિધેયો છે કે જેથી \(f\left(\frac{1}{4}\right)=0, f\left(\frac{1}{2}\right)=0, f(1)=1\) અને \(g\left(\frac{3}{4}\right)=0, g(1)=2 .\) ,તો \((-2,2)\) માં, \(f(x) g^{\prime \prime}(x)+f^{\prime}(x) g^{\prime}(x)=0\) ના ઉકેલોની ન્યૂનતમ સંખ્યા \(\dots\dots\)છે.

  1. A \(0\)
  2. B \(2\)
  3. C \(4\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(4\)

Step-by-step Solution

Detailed explanation

Let \(h(x)=f(x) g^{\prime}(x) \rightarrow 5\) roots \(\because f ( x )\) is even \(\Rightarrow\) \(f \left(\frac{1}{4}\right)= f \left(\frac{1}{2}\right)= f \left(-\frac{1}{2}\right)= f \left(\frac{1}{4}\right)=0\) \(g ( x )\) is even…
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