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JEE Mains · Maths · STD 11 - 7. binomial theoram

ધારો કે \(m, n \in N\) અને ગુ.સા.અ. \(\operatorname{gcd}(2, n)=1\). જો \(30\left(\begin{array}{l}30 \\ 0\end{array}\right)+29\left(\begin{array}{l}30 \\ 1\end{array}\right)+\ldots+2\left(\begin{array}{l}30 \\ 28\end{array}\right)+1\left(\begin{array}{l}30 \\ 29\end{array}\right)= n .2^{ m }\) તો \(n + m=.......\) (અહીં \(\left.\left(\begin{array}{l} n \\ k \end{array}\right)={ }^{ n } C _{ k }\right)\)

  1. A \(45\)
  2. B \(56\)
  3. C \(42\)
  4. D \(36\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(45\)

Step-by-step Solution

Detailed explanation

\(30\left({ }^{30} C _{0}\right)+29\left({ }^{30} C _{1}\right)+\ldots+2\left({ }^{30} C _{28}\right)+1\left({ }^{30} C _{29}\right)\) \(=30\left({ }^{30} C _{30}\right)+29\left({ }^{30} C _{29}\right)+\ldots \ldots+2\left({ }^{30} C _{2}\right)+1\left({ }^{30} C _{1}\right)\)…
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