ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 11 - 7. binomial theoram

\(\left(\frac{4 x}{5}+\frac{5}{2 x^2}\right)^9\) ના વિસ્તરણ માં \(x^{-6}\) નો સહગુણક \(..........\).

  1. A \(5041\)
  2. B \(5042\)
  3. C \(5043\)
  4. D \(5040\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(5040\)

Step-by-step Solution

Detailed explanation

\(\left(\frac{4 x}{5}+\frac{5}{2 x^2}\right)^9\) Now, \(T _{ r +1}={ }^9 C _{ r } \cdot\left(\frac{4 x }{5}\right)^{9- r }\left(\frac{5}{2 x ^2}\right)^{ r }\) \(={ }^9 C _{ r } \cdot\left(\frac{4}{5}\right)^{9- r }\left(\frac{5}{2}\right)^{ r } \cdot x ^{9-3 r }\) Coefficient…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app