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JEE Mains · Maths · STD 12 - 1. relation and function

ધારો કે \(f ^1( x )=\frac{3 x +2}{2 x +3}, x \in R -\left\{\frac{-3}{2}\right\}\) છે. \(n \geq 2\), માટે \(f ^{ n }( x )= f ^1 0 f ^{ n -1}( x )\) પ્રમાણે વ્યાખ્યાયિત કરો.જો \(f ^5( x )=\frac{ ax + b }{ bx + a }, \operatorname{gcd}( a , b )=1\), જ્યાં \(a\) અને \(b\) પરસ્પર અવિભાજ્ય છે,તો  \(a+b=............\).

  1. A \(3124\)
  2. B \(3123\)
  3. C \(3126\)
  4. D \(3125\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(3125\)

Step-by-step Solution

Detailed explanation

\(f^1(x)=\frac{3 x+2}{2 x+3}\) \(\Rightarrow f^2(x)=\frac{13 x+12}{12 x+13}\) \(\Rightarrow f^3(x)=\frac{63 x+62}{62 x+63}\) \(\therefore f^5(x)=\frac{1563 x+1562}{1562 x+1563}\) \(a+b=3125\)
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