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JEE Mains · Maths · STD 11 - 8. sequence and series

\(\sum_{r=1}^{20}\left(r^{2}+1\right)(r !)\) ની કિમંત મેળવો.

  1. A \(22\,!-21 !\)
  2. B \(22\, !-2(21 \,!)\)
  3. C \(21\, !-2 (20\,!)\)
  4. D \(21 \,!-20\, !\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(22\, !-2(21 \,!)\)

Step-by-step Solution

Detailed explanation

\(\sum_{x=1}^{20}\left(r^{2}+1\right) r !\) \(\sum_{x=1}^{20}\left((r+1)^{2}-2 r\right) r !\) \(\sum_{x=1}^{20}((r+1)(r+1) !-r \cdot r !)-\sum_{r=1}^{20} r \cdot r !\) \(\sum_{x=1}^{20}((r+1)(r+1) !-r \cdot r !)-\sum_{r=1}^{20}((r+1) !-r !)\) \(=(21.21-1)-(\lfloor 21-1)\)…
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