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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

બિંદુ \(\mathrm{P}(\sqrt{5}, \sqrt{5})\) માંથી પસાર થતી એક રેખા દીર્ઘવૃત્ત \(\frac{\mathrm{x}^2}{36}+\frac{\mathrm{y}^2}{25}=1\) ને \(A\) અને \(B\) પર એવી રીતે છેદે છે કે \((P A) .(P B)\) મહત્તમ છે. તો \(5\left(P A^2+P B^2\right)\) = __________

  1. A \(218\)
  2. B \(377\)
  3. C \(290\)
  4. D \(338\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(338\)

Step-by-step Solution

Detailed explanation

Given ellipse is \(\frac{x^2}{36}+\frac{y^2}{25}=1\) Any point on line \(A B\) can be assumed as \(\mathrm{Q}(\sqrt{5}+\mathrm{r} \cos \theta, \sqrt{5}+\mathrm{r} \sin \theta)\) Putting this in equation of ellipse, we get…
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