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JEE Mains · Maths · STD 12 - 9. differential equations

અહી \(\mathrm{y}=\mathrm{y}(\mathrm{x})\) એ વિકલ સમીકરણ \(\left((x+2) e^{\left(\frac{y+1}{x+2}\right)}+(y+1)\right) d x=(x+2) d y, y(1)=1\) નો ઉકેલ દર્શાવે છે . જો  \(y=y(x)\) નો પ્રદેશ \((\alpha, \beta)\) હોય તો \(|\alpha+\beta|\) ની કિમંત મેળવો.

  1. A \(3\)
  2. B \(4\)
  3. C \(5\)
  4. D \(9\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4\)

Step-by-step Solution

Detailed explanation

\(y+1=Y \Rightarrow d y=d Y\) \(x+2=X \Rightarrow d x=d X\) \(\Rightarrow\left(X e^{\frac{Y}{x}}+Y\right) d X=X d Y\) \(\Rightarrow X d Y-Y d X=X e^{Y / x} d X\) \(\Rightarrow d\left(\frac{Y}{X}\right) e^{-\frac{Y}{x}}=\frac{d X}{X}\) \(-e^{-y / x}=\ell n|x|+c\)…
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