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JEE Mains · Maths · STD 12 - 8. Application and integration

વક્રો \(y=\sin x+\cos x\) અને \(\mathrm{y}=|\cos \mathrm{x}-\sin \mathrm{x}|\) અને રેખાઓ \(\mathrm{x}=0, \mathrm{x}=\frac{\pi}{2}\) દ્વારા આવૃત પ્રદેશનું ક્ષેત્રફળ મેળવો.

  1. A \(2 \sqrt{2}(\sqrt{2}-1)\)
  2. B \(2(\sqrt{2}+1)\)
  3. C \(4(\sqrt{2}-1)\)
  4. D \(2 \sqrt{2}(\sqrt{2}+1)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2 \sqrt{2}(\sqrt{2}-1)\)

Step-by-step Solution

Detailed explanation

\(\mathrm{A}=\int_{0}^{\pi / 2}((\sin \mathrm{x}+\cos \mathrm{x})-|\cos \mathrm{x}-\sin \mathrm{x}|) \mathrm{dx}\) \(\mathrm{A}=\int_{0}^{\pi / 2}((\sin \mathrm{x}+\cos \mathrm{x})-(\cos \mathrm{x}-\sin \mathrm{x})) \mathrm{dx}\)…
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