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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

વિયોજન અચળાંક \(K_a\) ના મૂલ્યો નીચે આપેલા છે
      ઍસિડ       \(K_a\)
      \(HCN\)       \(6.2\times 10^{-10}\)
      \(HF\)       \(7.2\times 10^{-4}\)
      \(HNO_2\)       \(4.0\times 10^{-4}\)
તો બેઇઝ  \(CN^-,F^-\) અને \(NO_2^-\) ની બેઝિક પ્રબળાતાનો સાચો વધતો ક્રમ જણાવો.

  1. A \(F^- < CN^- < NO_2^-\)
  2. B \(NO_2^- < CN^- < F^-\)
  3. C \(F^- < NO_2^- < CN^-\)
  4. D \(NO_2^- < F^- < CN^-\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(F^- < NO_2^- < CN^-\)

Step-by-step Solution

Detailed explanation

Higher the value of \(K_a\) lower will be the value of \(pK_a\) \(i.e.\) higher will be the acidic nature. Further since \(CN^-, F^-\) and \(NO_2^-\) are conjugate base of the acids \(HCN, HF\) and \(HNO_2\) respectively hence the correct order of base strength will be…
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