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JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry

સંયોજનોના રંગોની તીવ્રતાનો સાચો ક્રમ છે:

  1. A \(\left[{Ni}({CN})_{4}\right]^{2-}>\left[{NiCl}_{4}\right]^{2-}>\left[{Ni}\left({H}_{2} {O}\right)_{6}\right]^{2+}\)
  2. B \(\left[{NiCl}_{4}\right]^{2-}>\left[{Ni}({CN})_{4}\right]^{2-}>\left[{Ni}\left({H}_{2} {O}\right)_{6}\right]^{2+}\)
  3. C \(\left[{NiCl}_{4}\right]^{2-}>\left[{Ni}\left({H}_{2} {O}\right)_{6}\right]^{2+}>\left[{Ni}({CN})_{4}\right]^{2-}\)
  4. D \(\left[{Ni}\left({H}_{2} {O}\right)_{6}\right]^{2+}>\left[{NiCl}_{4}\right]^{2-}>\left[{Ni}({CN})_{4}\right]^{2-}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\left[{NiCl}_{4}\right]^{2-}>\left[{Ni}\left({H}_{2} {O}\right)_{6}\right]^{2+}>\left[{Ni}({CN})_{4}\right]^{2-}\)

Step-by-step Solution

Detailed explanation

\(\left[{NiCl}_{4}\right]^{-2-}>\left[{Ni}\left({H}_{2} {O}\right)_{6}\right]^{-2+}>\left[{Ni}({CN})_{4}\right]^{-2-}\) Splitting energy order : \(\Delta_{{t}}<\Delta_{0} \quad<\Delta_{{sq}}\) absorbed energy order :…
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