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JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization

સામાન્ય વિશ્લેષણ દ્વારા, સંયોજન (X) ના 1.00g માંથી 1.79g મેગ્નેશિયમ પાયરોફોસ્ફેટ પ્રાપ્ત થયું. સંયોજન (X) માં ફોસ્ફરસની ટકાવારી છે: (નજીકના પૂર્ણાંકમાં)
(આપેલ છે, મોલર દળ \(g~mol^{-1}\) માં; O=16, Mg=24, P=31)

A 50
B 30
C 20
D 40

Verified Solution

Answer & Solution

Correct Answer

(A) 50

Step-by-step Solution

Detailed explanation

\(P\) ની ટકાવારી \(= \frac{n_{Mg_{2}P_{2}O_{7}} \times 2 \times 31}{w_{(unknown~compound)}} \times 100\) \(= \frac{(\frac{1.79}{222} \times 2 \times 31)}{1} \times 100\) \(= 49.99\% \approx 50\%\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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