પ્રતિનીધી (મુખત્યાર) ધાતુ સંકીર્ણ \([M(en)(SCN)_4]\) માં ઉત્મદંતી લિગેન્ડની સંખ્યા \(..........\) છે. \([en =\) ઈથિલીનડાયએમાઈન]

A \(6\)
B \(8\)
C \(10\)
D \(4\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(4\)

Step-by-step Solution

Detailed explanation

\(\left[ M ( en )( SCN )_4\right]\) Ambidentate ligand means two ligand site, so ambidentate ligand is \(SCN\).

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

\(975\, {~K}\) પર નીચે આપેલ રાસાયણિક પ્રક્રિયા માટે નીચેની માહિતી મેળવવામાં આવ્યો હતો. \(2 {NO}_{({g})}+2 {H}_{2({~g})} \rightarrow {N}_{2({~g})}+2 {H}_{2} {O}_{({g})}\)

	\([NO]\) \({mol} {L}^{-1}\)	\({H}_{2}\) \({mol} {L}^{-1}\)	વેગ \({mol}L^{-1}\) \(s^{-1}\)
\((A)\)	\(8 \times 10^{-5}\)	\(8 \times 10^{-5}\)	\(7 \times 10^{-9}\)
\((B)\)	\(24 \times 10^{-5}\)	\(8 \times 10^{-5}\)	\(2.1 \times 10^{-8}\)
\((C)\)	\(24 \times 10^{-5}\)	\(32 \times 10^{-5}\)	\(8.4 \times 10^{-8}\)

\({NO}\)ના સંદર્ભમાં પ્રક્રિયાનો ક્રમ \(....\) છે.

JEE Mains 2021 Medium

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