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JEE Mains · Chemistry · STD 11 - 3. Classification of elements and periodicity in properties

\(Na\) નો પ્રથમ આયનીકરણ પોટેન્શિયલ \(5.1\, eV\) છે. તો \(Na^+\) ની ઇલેક્ટ્રોન પ્રાપ્તિ એન્થાલ્પીનું મૂલ્ય ................. \(\mathrm{eV}\) શોધો. 

  1. A \(-2.55\)
  2. B \(-5.1\)
  3. C \(-10.2\)
  4. D \(+2.55\)
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Answer & Solution

Correct Answer

(B) \(-5.1\)

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Detailed explanation

\(\mathrm{Na} \rightarrow \mathrm{Na}^{+}+\mathrm{e}^{-} \quad \mathrm{IE}=5.1 \mathrm{eV} \ldots \ldots\) \(\mathrm{Na}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Na}\) Second reaction is inverse of first reaction, therefore electron goes enthalapy of \(N a^{+}\) is reverse of…
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