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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

\(KI\) ના \(20\%\) (mass/mass) દ્રાવણની મોલાલિટી  થશે ? (\(KI\)નુ મોલર દળ \( = 166\,g\,mol^{-1}\))

  1. A \(1.08\)
  2. B \(1.48\)
  3. C \(1.51\)
  4. D \(1.35\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1.51\)

Step-by-step Solution

Detailed explanation

\(20\%\,w/w\,KI\) Mass of solute \((KI) = 20\,g\) Mass of solvent \(= 100-20 = 80\,g\) Molar mass of \(KI = 38+128 = 166\) Molality \( = \frac{{gm\,(solute)}}{{mw\, \times Kg\,(solvent)}} = \frac{{20 \times 1000}}{{166 \times 80}} = 1.506 = 1.51\)
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