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JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure

અણુઓમાં બંધની વધતી જતી આયનીય લાક્ષણિકતાના ક્રમમાં ગોઠવો.
[\(\mathrm{LiF}, \mathrm{K}_2 \mathrm{O}, \mathrm{N}_2, \mathrm{SO}_2\) અને \(\mathrm{CIF}_3\)]

  1. A \(\mathrm{CIF}_3<\mathrm{N}_2<\mathrm{SO}_2<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}\)
  2. B \(\mathrm{LiF}<\mathrm{K}_2 \mathrm{O}<\mathrm{CIF}_3<\mathrm{SO}_2<\mathrm{N}_2\)
  3. C \(\mathrm{N}_2<\mathrm{SO}_2<\mathrm{CIF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}\)
  4. D \(\mathrm{N}_2<\mathrm{CIF}_3<\mathrm{SO}_2<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\mathrm{N}_2<\mathrm{SO}_2<\mathrm{CIF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}\)

Step-by-step Solution

Detailed explanation

આયનીય લાક્ષણિકતાનો વધતો ક્રમ \(\mathrm{N}_2<\mathrm{SO}_2<\mathrm{ClF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}\) આયનીય લાક્ષણિકતા વિદ્યુતઋણતાના તફાવત (બંધ ધ્રુવીયતા) પર આધાર રાખે છે.
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