JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
Arrange the bonds in order of increasing ionic character in the molecules.
[\(\mathrm{LiF}, \mathrm{K}_2 \mathrm{O}, \mathrm{N}_2, \mathrm{SO}_2\) and \(\mathrm{CIF}_3\)]
- A \(\mathrm{CIF}_3<\mathrm{N}_2<\mathrm{SO}_2<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}\)
- B \(\mathrm{LiF}<\mathrm{K}_2 \mathrm{O}<\mathrm{CIF}_3<\mathrm{SO}_2<\mathrm{N}_2\)
- C \(\mathrm{N}_2<\mathrm{SO}_2<\mathrm{CIF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}\)
- D \(\mathrm{N}_2<\mathrm{CIF}_3<\mathrm{SO}_2<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{N}_2<\mathrm{SO}_2<\mathrm{CIF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}\)
Step-by-step Solution
Detailed explanation
Increasing order of ionic character \(\mathrm{N}_2<\mathrm{SO}_2<\mathrm{ClF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}\) Ionic character depends upon difference of electronegativity (bond polarity).
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