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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

\(298\,K\) પર \(A \rightleftharpoons B\) પ્રક્રિયા માટે \(\log K\) નું મુલ્ય \(.....\) છે.(નજીકનો પૂર્ણાક) આપેલ : \(\Delta H ^{\circ}=-54.07\,kJ\,mol ^{-1}\) \(\Delta S ^{\circ}=10\,J\,K ^{-1}\,mol ^{-1}\) \((2.303 \times 8.314 \times 298=5705\) લો.)

  1. A \(11\)
  2. B \(12\)
  3. C \(14\)
  4. D \(10\)
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Answer & Solution

Correct Answer

(D) \(10\)

Step-by-step Solution

Detailed explanation

\(\Delta G ^0=\Delta H ^0- T \Delta S\) \(\Rightarrow \Delta G ^0=(-54070-10 \times 298)\) Also, \(\Delta G ^0=(-2.303 RT \log K )\) \(\Rightarrow(-54070-10 \times 298)\) \(=(-2.303 \times 8.134 \times 298 \log K )\) \(\Rightarrow \log K =10 \text { Ans: } 10\)
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