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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

\(100\, {~mL}\) \({Na}_{3} {PO}_{4}\) દ્રાવણમાં \(3.45\, {~g}\) સોડિયમ છે. દ્રાવણની મોલારીટી \(.....\times 10^{-2}\) \(\operatorname{mol} \,{L}^{-1} \cdot(\) નજીકના પૂર્ણાંકમાં \()\) [અણુ દળ - \({Na}: 23.0\, {u}, {O}: 16.0\, {u}, {P}: 31.0 \,{u}]\)

  1. A \(500\)
  2. B \(50\)
  3. C \(5\)
  4. D \(0.50\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(50\)

Step-by-step Solution

Detailed explanation

\({Na}_{3} {PO}_{4} \longrightarrow \quad3 {Na}\) \(\frac{1}{3} \times \frac{3.45}{23} {~mol} \quad\) \(3.45 {~g}\) \(\quad\quad\quad\quad\quad\quad\quad\frac{3.45}{23} {~mol}\) therefore molarity of \({Na}_{3} {PO}_{4}\) Solution =…
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