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GUJCET · Maths · Relations and Functions

વિધેય \(f:[2, \infty) \rightarrow \mathrm{R}, f(x)=x^2-4 x+5\) દ્વારા વ્યાખ્યાયિત વિધેય હોય, તો \(f\) નો વિસ્તાર = _________.

  1. A R
  2. B \([1, \infty)\)
  3. C \([4, \infty)\)
  4. D \([5, \infty)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \([1, \infty)\)

Step-by-step Solution

Detailed explanation

\(f(x) = x^2 - 4x + 5 = (x-2)^2 + 1\) \(\text{For } x \in [2, \infty): \text{min } (x-2)^2 = 0 \text{ at } x=2\)
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