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GUJCET · Maths · Relations and Functions
Function \(f:[2, \infty) \rightarrow R , f(x)=x^2-4 x+5\) is defined then, range of \(f\) is \(=\) ____________ .
- A R
- B \([1, \infty)\)
- C \([4, \infty)\)
- D \([5, \infty)\)
Answer & Solution
Correct Answer
(B) \([1, \infty)\)
Step-by-step Solution
Detailed explanation
\(f(x) = x^2 - 4x + 5 = (x-2)^2 + 1\) \(\text{For } x \in [2, \infty): \text{min } (x-2)^2 = 0 \text{ at } x=2\)
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