JEE Mains · Physics · STD 11 - 3.1 vectors
When vector \(\overrightarrow{ A }=2 \hat{ i }+3 \hat{ j }+2 \hat{ k }\) is subtracted from vector \(\vec{B}\), it gives a vector equal to \(2 \hat{j}\). Then the magnitude of vector \(\vec{B}\) will be:
- A \(\sqrt{13}\)
- B \(\sqrt{33}\)
- C \(\sqrt{6}\)
- D \(\sqrt{5}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{33}\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ B }-\overrightarrow{ A }=2 j\) \(\overrightarrow{ B }=2 \hat{ i }+5 \hat{ j }+2 \hat{ k }\) \(|\overrightarrow{ B }|=\sqrt{33}\)
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