JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A transformer has an efficiency of \(80 \%\) and works at \(10 \mathrm{~V}\) and \(4 \mathrm{~kW}\). If the secondary voltage is \(240 \mathrm{~V}\), then the current in the secondary coil is _______.
- A \(1.59 \mathrm{~A}\)
- B \(13.33 \mathrm{~A}\)
- C \(1.33 \mathrm{~A}\)
- D \(15.1 \mathrm{~A}\)
Answer & Solution
Correct Answer
(B) \(13.33 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
\(\text { Efficiency }=\frac{E_{\mathrm{S}} I_{\mathrm{S}}}{\mathrm{E}_{\mathrm{P}} \mathrm{I}_{\mathrm{P}}}\) \(0.8=\frac{240 \mathrm{I}_{\mathrm{S}}}{4000}\) \(\mathrm{I}_{\mathrm{S}}=\frac{3200}{240}=13.33 \mathrm{~A}\)
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