JEE Mains · Maths · STD 11 - 12. limits
If \(\lim _{n \rightarrow \infty}\left(\sqrt{n^{2}-n-1}+n \alpha+\beta\right)=0\) then \(8(\alpha+\beta)\) is equal to :
- A \(4\)
- B \(-8\)
- C \(-4\)
- D \(8\)
Answer & Solution
Correct Answer
(C) \(-4\)
Step-by-step Solution
Detailed explanation
\(\lim _{n \rightarrow \infty} n\left(1-\frac{n+1}{n^{2}}\right)^{\frac{1}{2}}+\alpha n+\beta=0\)…
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