JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2024
- Hard
- MCQ
The electric current through a wire varies with time as \(I=I_0+\beta t\). where \(I_0=20 \mathrm{~A}\) and \(\beta=3 \mathrm{~A} / \mathrm{s}\). The amount of electric charge crossed through a section of the wire in \(20 \mathrm{~s}\) is :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(1000 \ \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Given that
Current \(I=I_0+\beta t\)
\( I_0=20 \mathrm{~A} \)
\( \beta=3 \mathrm{~A} / \mathrm{s}\)
\( \mathrm{I}=20+3 \mathrm{t} \)
\( \frac{\mathrm{dq}}{\mathrm{dt}}=20+3 \mathrm{t} \)
\( \int_0^q \mathrm{dq}=\int_0^{20}(20+3 \mathrm{t}) \mathrm{dt} \)
\( \mathrm{q}=\int_0^{20} 20 \mathrm{dt}+\int_0^{20} 3 \mathrm{tdt} \)
\( \mathrm{q}=\left[20 \mathrm{t}+\frac{3 \mathrm{t}^2}{2}\right]_0^{20}=1000\ \mathrm{C}\)
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