JEE Mains · Physics · STD 11 - 3.2 motion in plane
A ball having kinetic energy KE, is projected at an angle of \(60^{\circ}\) from the horizontal. What will be the kinetic energy of ball at the highest point of its flight ?
- A \(\frac{(\mathrm{KE})}{8}\)
- B \(\frac{(\mathrm{KE})}{2}\)
- C \(\frac{(\mathrm{KE})}{16}\)
- D \(\frac{(\mathrm{KE})}{4}\)
Answer & Solution
Correct Answer
(D) \(\frac{(\mathrm{KE})}{4}\)
Step-by-step Solution
Detailed explanation
Initial K.E, \(\text { K.E. }=\frac{1}{2} \mathrm{mu}^2\) Speed at heighest point…
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