JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
An experiment is performed to determine the \(I-V\) characteristics of a Zener diode, which has a protective resistance of \(R = 100 \,\Omega ,\) and a maximum power of dissipation rating of \(1\,W\) .The minimum voltage range of the \(DC\) source in the circuit is
- A \(0-5\,\,V\)
- B \(0-24\,\,V\)
- C \(0-12\,\,V\)
- D \(0-8\,\,V\)
Answer & Solution
Correct Answer
(C) \(0-12\,\,V\)
Step-by-step Solution
Detailed explanation
The minimum voltage range of \(DC\) source is given by \(\mathrm{V}^{2}=\mathrm{PR}\) \( \because \,\, \mathrm{P}=1\,watt\), \(\mathrm{R}=100 \Omega\) \(=1 \times 100\) \(\therefore \mathrm{V}=10 \mathrm{volt}\)
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