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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2016
  • Medium
  • MCQ

An experiment is performed to determine the \(I-V\) characteristics of a Zener diode, which has a protective resistance of \(R = 100 \,\Omega ,\) and a maximum power of dissipation rating of \(1\,W\) .The minimum voltage range of the \(DC\) source in the circuit is

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Answer & Solution

Correct Answer

(C) \(0-12\,\,V\)

Step-by-step Solution

Detailed explanation

The minimum voltage range of \(DC\) source is given by

\(\mathrm{V}^{2}=\mathrm{PR}\)

\( \because \,\, \mathrm{P}=1\,watt\),

\(\mathrm{R}=100 \Omega\)

\(=1 \times 100\)

\(\therefore \mathrm{V}=10 \mathrm{volt}\)

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