JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2018
- Medium
- Numerical
Unpolarized light of intensity \(I\) passes through an ideal polarizer \(A\) Another indentical polarizer \(B\) is placed behind \(A\) The intensity of light beyond \(B\) is found to be \(\frac{I}{2}\) Now another identical polarizer \(C\) is placed between \(A\) and \(B\). The intensity beyond \(B\) is now found to be \(\frac{I}{8}\) The angle between polarizer \(A\) and \(C\) is:......\(^o\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(45\)
Step-by-step Solution
Detailed explanation
\(\frac{I}{2} \cos ^{4} \theta=\frac{I}{8} \Rightarrow \cos ^{4} \theta=\frac{1}{4}\)
\(\Rightarrow \cos \theta=\frac{1}{\sqrt{2}}\) or, \(\theta=45^{\circ}\)
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