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JEE Mains · Physics · STD 12 - 10. Wave optics

Unpolarized light of intensity \(I\) passes through an ideal polarizer \(A\) Another indentical polarizer \(B\) is placed behind \(A\) The intensity of light beyond \(B\) is found to be \(\frac{I}{2}\) Now another identical polarizer \(C\) is placed between \(A\) and \(B\). The intensity beyond \(B\) is now found to be \(\frac{I}{8}\) The angle between polarizer \(A\) and \(C\) is:......\(^o\)

  1. A \(30\)
  2. B \(45\)
  3. C \(60\)
  4. D \(0\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(45\)

Step-by-step Solution

Detailed explanation

\(\frac{I}{2} \cos ^{4} \theta=\frac{I}{8} \Rightarrow \cos ^{4} \theta=\frac{1}{4}\) \(\Rightarrow \cos \theta=\frac{1}{\sqrt{2}}\) or, \(\theta=45^{\circ}\)
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