JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2023
- Medium
- MCQ
Statement \(I :\) When a Si sample is doped with Boron, it becomes \(P\) type and when doped by Arsenic it becomes \(N-\)type semi conductor such that \(P-\)type has excess holes and N-type has excess electrons. Statement \(II\) : When such \(P-\)type and \(N-\)type semi-conductors, are fused to make a junction, a current will automatically flow which can be detected with an externally connected ammeter. In the light of above statements, choose the most appropriate answer from the options given below.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) Statement \(I\) is correct but statement \(II\) is incorrect
Step-by-step Solution
Detailed explanation
Statement\(-I\) is correct
When \(P-N\) junction is formed an electric field is generated form \(N\)-side to \(P\)-side due to which barrier potential arises \& majority charge carrier can not flow through the junction due to barrier potential so current is \(zero\) unless we apply forward bias voltage.
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