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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2016
  • Medium
  • MCQ

The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is

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Answer & Solution

Correct Answer

(A) \(0.4\)

Step-by-step Solution

Detailed explanation

Efficiency of heat engine is given by

\(\eta  = \frac{W}{Q} = 1 - \frac{{{C_V}}}{{{C_P}}} = \frac{R}{{{C_P}}} = \frac{R}{{\frac{{5R}}{2}}} = \frac{2}{5}\)

\(\left( {{C_P} - {C_V} = R} \right)\)

For monoatomic gas \({C_P} = \frac{5}{2}R.\)

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