JEE Mains · Physics · STD 11 - 11. thermodynamics
The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is
- A \(0.4\)
- B \(1.5\)
- C \(0.6\)
- D \(0.67\)
Answer & Solution
Correct Answer
(A) \(0.4\)
Step-by-step Solution
Detailed explanation
Efficiency of heat engine is given by \(\eta = \frac{W}{Q} = 1 - \frac{{{C_V}}}{{{C_P}}} = \frac{R}{{{C_P}}} = \frac{R}{{\frac{{5R}}{2}}} = \frac{2}{5}\) \(\left( {{C_P} - {C_V} = R} \right)\) For monoatomic gas \({C_P} = \frac{5}{2}R.\)
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