JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2019
- Hard
- MCQ
The figure represents a voltage regulator circuit using a Zener diode. The breakdown voltage of the Zener diode is \(6\,V\) and the load resistance is \(R_L= 4\,k\Omega .\) The series resistance of the circuit is \(R_i = 1\,k\Omega .\) If the battery voltage \(V_B\) varies from \(8\,V\) to \(16\,V,\) what are the minimum and maximum values of the current through Zener diode?

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Answer & Solution
Correct Answer
(D) \(0.5\,mA;\,\,8.5\,mA\)
Step-by-step Solution
Detailed explanation
\({{\text{V}}_{{\text{breaddwon }}}} = 6{\text{V}},\) \({{\text{R}}_{\text{L}}} = 4\,{\text{k}}\Omega ,\) \({{\text{R}}_{\text{i}}} = 1{\text{k}}\Omega \)
\({{\text{i}}_{\text{L}}} = \frac{6}{4} \times {10^{ - 3}} = \) \(1.5 \times {10^{ - 3}} = 1.5{\text{mA}}\)
\(\mathrm{i}_{\mathrm{i}}=2 \times 10^{-3}\)
\({\text{i}} = {{\text{i}}_1} - {{\text{i}}_{\text{L}}} = 0.5{\text{mA}} - \) minimum current
\(\mathrm{i}_{\mathrm{i}}=10 \times 10^{-3}=10 \mathrm{mA}\)
\(\operatorname{lmax}=8.5 \mathrm{mA}\)
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