JEE Mains · Physics · STD 12 - 13. Nuclei
A nucleus has mass number \(A_1\) and volume \(V_1\). Another nucleus has mass number \(A_2\) and volume \(V_2\). If relation between mass number is \(A_2=4 A_1\), then \(\frac{V_2}{V_1}=\)_______.
- A \(3\)
- B \(4\)
- C \(5\)
- D \(6\)
Answer & Solution
Correct Answer
(B) \(4\)
Step-by-step Solution
Detailed explanation
For a nucleus Volume: \(\mathrm{V}=\frac{4}{3} \pi \mathrm{R}^3\) \(\mathrm{R}=\mathrm{R}_0(\mathrm{~A})^{1 / 3}\) \(\mathrm{~V}=\frac{4}{3} \pi \mathrm{R}_0^3 \mathrm{~A}\) \(\Rightarrow \frac{V_2}{V_1}=\frac{A_2}{A_1}=4\)
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