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JEE Mains · Physics · STD 12 - Nuclei
  • JEE Mains 2024
  • Hard
  • Numerical

A nucleus has mass number \(A_1\) and volume \(V_1\). Another nucleus has mass number \(A_2\) and volume \(V_2\). If relation between mass number is \(A_2=4 A_1\), then \(\frac{V_2}{V_1}=\)_______.

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Answer & Solution

Correct Answer

(B) \(4\)

Step-by-step Solution

Detailed explanation

For a nucleus

Volume: \(\mathrm{V}=\frac{4}{3} \pi \mathrm{R}^3\)

\(\mathrm{R}=\mathrm{R}_0(\mathrm{~A})^{1 / 3}\)

\(\mathrm{~V}=\frac{4}{3} \pi \mathrm{R}_0^3 \mathrm{~A}\)

\(\Rightarrow \frac{V_2}{V_1}=\frac{A_2}{A_1}=4\)

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