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JEE Mains · Physics · STD 12 -Electromagnetic induction
  • JEE Mains 2023
  • Easy
  • Numerical

A wire of length \(1\,m\) moving with velocity \(8\,m / s\) at right angles to a magnetic field of \(2\,T\). The magnitude of induced emf, between the ends of wire will be \(............\,V\)

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Answer & Solution

Correct Answer

(D) \(16\)

Step-by-step Solution

Detailed explanation

Induced emf across the ends \(= Bv \ell\)

\(=2 \times 8 \times 1=16\,V\)

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