JEE Mains · Physics · STD 12 - 1. Electric charges and fields
Two point charges \(2 q\) and \(q\) are placed at vertex \(A\) and centre of face CDEF of the cube as shown in figure. The electric flux passing through the cube is :

- A \(\frac{3 q}{\varepsilon_0}\)
- B \(\frac{ q }{\varepsilon_0}\)
- C \(\frac{3 q}{2 \varepsilon_0}\)
- D \(\frac{3 q}{4 \varepsilon_0}\)
Answer & Solution
Correct Answer
(D) \(\frac{3 q}{4 \varepsilon_0}\)
Step-by-step Solution
Detailed explanation
\(\phi=\frac{ Q _{\text {in }}}{\varepsilon_0}\) \(\phi=\frac{\frac{q}{4}+\frac{q}{2}}{\varepsilon_0}=\frac{3 q}{4 \varepsilon_0}\)
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