JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
Four particles each of mass \(1 \mathrm{~kg}\) are placed at four corners of a square of side \(2 \mathrm{~m}\). Moment of inertia of system about an axis perpendicular to its plane and passing through one of its vertex is_________ \(\mathrm{kgm}^2\).

- A \(35\)
- B \(16\)
- C \(42\)
- D \(75\)
Answer & Solution
Correct Answer
(B) \(16\)
Step-by-step Solution
Detailed explanation
\( \mathrm{I}=m a^2+m a^2+\mathrm{m}(\sqrt{2} \mathrm{a})^2 \) \( =4 \mathrm{ma}^2 \) \( =4 \times 1 \times(2)^2=16\)
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