JEE Mains · Physics · STD 12 - Atoms
- JEE Mains 2025
- Easy
- MCQ
Considering the Bohr model of hydrogen like atoms, the ratio of the ratio of the radius \(5^{\text {th}}\) orbit of the electron in \(\mathrm{Li}^{2+}\) and \(\mathrm{He}^{+}\) is _______.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\frac{2}{3}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{r}=\mathrm{r} \cdot \frac{\mathrm{n}^2}{2}\)
for \(\mathrm{Li}^{2+}\)
\(r_5=r \cdot \frac{25}{3}\)
for \(\mathrm{He}^{+}\)
\(\begin{aligned}
& \mathrm{r}_5=\mathrm{r} \cdot \frac{25}{2} \\
& \therefore \frac{\mathrm{r}_{\mathrm{Li}^{2+}}}{\mathrm{r}_{\mathrm{He}^{+}}}=\frac{2}{3}
\end{aligned}\)
for \(\mathrm{Li}^{2+}\)
\(r_5=r \cdot \frac{25}{3}\)
for \(\mathrm{He}^{+}\)
\(\begin{aligned}
& \mathrm{r}_5=\mathrm{r} \cdot \frac{25}{2} \\
& \therefore \frac{\mathrm{r}_{\mathrm{Li}^{2+}}}{\mathrm{r}_{\mathrm{He}^{+}}}=\frac{2}{3}
\end{aligned}\)
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