JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
A common emitter amplifier circuit, built using an \(npn\) transistor, is shown in the figure. Its \(dc\) current gain is \(250\), \(R_C = 1\,k\, \Omega \) and \(V_{CC} = 10\,V\). What is the minimum base current for \(V_{CE}\) to reach saturation?.........\(\mu A\)
- A \(7\)
- B \(40\)
- C \(10\)
- D \(100\)
Answer & Solution
Correct Answer
(B) \(40\)
Step-by-step Solution
Detailed explanation
At saturation state, \(V_{CE}\) becomes zero \(\Rightarrow \mathrm{i}_{\mathrm{C}}\) \(=\frac{10 \mathrm{V}}{1000 \Omega}=10 \mathrm{mA}\) Now current gain factor \(\beta=\frac{\mathrm{i}_{\mathrm{C}}}{\mathrm{i}_{\mathrm{B}}}\)…
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