JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
Two charged particles, having same kinetic energy, are allowed to pass through a uniform magnetic field perpendicular to the direction of motion. If the ratio of radii of their circular paths is \(6: 5\) and their respective masses ratio is \(9: 4\). Then, the ratio of their charges will be.
- A \(8: 5\)
- B \(5: 4\)
- C \(5: 3\)
- D \(8: 7\)
Answer & Solution
Correct Answer
(B) \(5: 4\)
Step-by-step Solution
Detailed explanation
Radius of circular path \(R =\frac{\sqrt{2 mk }}{ qB }\) \(q =\frac{\sqrt{2 mk }}{ RB }\) \(\frac{ q _{1}}{ q _{2}}=\sqrt{\frac{ m _{1}}{ m _{2}}} \times \frac{ R _{2}}{ R _{1}}=\sqrt{\frac{9}{4}} \times \frac{5}{6}=\frac{5}{4}\)
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