JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2023
- Medium
- Numerical
Two objects \(A\) and \(B\) are placed at \(15\,cm\) and \(25\,cm\) from the pole in front of a concave mirror having radius of curvature \(40 cm\). The distance between images formed by the mirror is \(..........\,cm\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(160\)
Step-by-step Solution
Detailed explanation
by mirror formula
\(\frac{1}{ v }+\frac{1}{ u }=\frac{1}{ f }\)
\(\frac{1}{ v _1}+\frac{1}{-15}=\frac{1}{(-20)}\)
\(\frac{1}{ v _1}=-\frac{1}{20}+\frac{1}{15}\)
\(=\frac{-3+4}{60}\)
\(v _1=60\,cm\)
\(\frac{1}{ v _2}+\frac{1}{(-25)}=\frac{1}{(-20)}\)
\(\frac{1}{ v _2}=\frac{-1}{20}+\frac{1}{25}\)
\(=\frac{-5+4}{100}=\frac{-1}{100}\)
\(v _2=-100\,cm\)
\(d =60+100=160\,cm\)
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