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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2023
  • Medium
  • Numerical

Two objects \(A\) and \(B\) are placed at \(15\,cm\) and \(25\,cm\) from the pole in front of a concave mirror having radius of curvature \(40 cm\). The distance between images formed by the mirror is \(..........\,cm\)

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Answer & Solution

Correct Answer

(C) \(160\)

Step-by-step Solution

Detailed explanation

by mirror formula

\(\frac{1}{ v }+\frac{1}{ u }=\frac{1}{ f }\)

\(\frac{1}{ v _1}+\frac{1}{-15}=\frac{1}{(-20)}\)

\(\frac{1}{ v _1}=-\frac{1}{20}+\frac{1}{15}\)

\(=\frac{-3+4}{60}\)

\(v _1=60\,cm\)

\(\frac{1}{ v _2}+\frac{1}{(-25)}=\frac{1}{(-20)}\)

\(\frac{1}{ v _2}=\frac{-1}{20}+\frac{1}{25}\)

\(=\frac{-5+4}{100}=\frac{-1}{100}\)

\(v _2=-100\,cm\)

\(d =60+100=160\,cm\)

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