JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
Two objects \(A\) and \(B\) are placed at \(15\,cm\) and \(25\,cm\) from the pole in front of a concave mirror having radius of curvature \(40 cm\). The distance between images formed by the mirror is \(..........\,cm\)
- A \(40\)
- B \(60\)
- C \(160\)
- D \(100\)
Answer & Solution
Correct Answer
(C) \(160\)
Step-by-step Solution
Detailed explanation
by mirror formula \(\frac{1}{ v }+\frac{1}{ u }=\frac{1}{ f }\) \(\frac{1}{ v _1}+\frac{1}{-15}=\frac{1}{(-20)}\) \(\frac{1}{ v _1}=-\frac{1}{20}+\frac{1}{15}\) \(=\frac{-3+4}{60}\) \(v _1=60\,cm\) \(\frac{1}{ v _2}+\frac{1}{(-25)}=\frac{1}{(-20)}\)…
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