JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2023
- Medium
- Numerical
Two transparent media having refractive indices \(1.0\) and \(1.5\) are separated by a spherical refracting surface of radius of curvature \(30\,cm\). The centre of curvature of surface is towards denser medium and a point object is placed on the principle axis in rarer medium at a distance of \(15\,cm\) from the pole of the surface. The distance of image from the pole of the surface is .......\(cm\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(30\)
Step-by-step Solution
Detailed explanation
\(\frac{\mu_2}{ v }-\frac{\mu_1}{ u }=\frac{\mu_2-\mu_1}{ R }\)
\(\frac{1.5}{ v }-\frac{1}{-15}=\frac{1.5-1}{30}=\frac{1}{60}\)
\(\frac{1.5}{ v }+\frac{1}{15}=\frac{1}{60}\)
\(\frac{1.5}{ v }=\frac{1}{60}-\frac{1}{15}=\frac{-1}{20}\)
\(\frac{1.5}{ v }=-\frac{1}{20} \Rightarrow v =-30\,cm\)
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