JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2018
- Hard
- MCQ
In a common emitter configuration with suitable bias, it is given than \(R_L\) is the load resistance and \(R_{BE}\) is small signal dynamic resistance (input side). Then, voltage gain, current gain and power gain are given, respectively, by: [ \(\beta \) is current gain, \(I_B\) , \(I_C\) , \(I_E\) are respectively base, collector and emitter currents]
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\beta \frac{{{R_L}}}{{{R_{BE}}}},\frac{{\Delta {I_C}}}{{\Delta {I_B}}},{\beta ^2}\frac{{{R_L}}}{{{R_{BE}}}}\)
Step-by-step Solution
Detailed explanation
Curent gain \(\beta=\frac{\Delta I_{C}}{I_{B}}\)
Voltage gain \(\mathrm{A}_{\mathrm{v}}=\) Current gain \(\times\) Resistance
\(\operatorname{gain}=\beta \frac{R_{L}}{R_{B E}}\)
Power gain \(A_{p}=(\text { Current gain })^{2} \times\) Resistance gain
\(=\beta^{2} \frac{R_{L}}{R_{B E}}\)
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